Magnetism Question 215
Question: The magnetic moment of a magnet of length 10 cm and pole strength 4.0 Am will be
[DPMT 2003]
Options:
A) $ 0.4 Am^{2} $
B) $ 1.6 Am^{2} $
C) $ 20 Am^{2} $
D) $ 8.0 Am^{2} $
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Answer:
Correct Answer: A
Solution:
$ M=mL=4\times 10\times {{10}^{-2}}=0.4A\times m^{2} $