Magnetism Question 218
Question: A small bar magnet has a magnetic moment 1.2 $ Am^2 $. The magnetic field at a distance 0.1 m on its axis will be :($ mu_0=4\pix10^{-7} T-m/A $)
[BHU 2003]
Options:
A) $1.2 \times 10^{-4}$ T
B) $2.4 \times 10^{-4}$ T
C) $2.4 \times 10^{- }$ T
D) $1.2 \times 10^{- }$ T
Show Answer
Answer:
Correct Answer: B
Solution:
$ B=\frac{{\mu _{0}}}{4\pi }.\frac{2M}{d^{3}}\Rightarrow B={{10}^{-7}}\times \frac{2\times 1.2}{{{( 0.1 )}^{3}}}=2.4\times {{10}^{-4}}T $
BETA
