Magnetism Question 228
Question: A bar magnet of magnetic moment $ 3.0 A-m^{2} $ is placed in a uniform magnetic field of $ 2\times {{10}^{-5}}T $ .If each pole of the magnet experiences a force of $ 6\times {{10}^{-4}}N $ , the length of the magnet is
Options:
A) 0.5 m
B) 0.3 m
C) 0.2 m
D) 0.1 m
Show Answer
Answer:
Correct Answer: D
Solution:
[d] $ F=mB $ or $ 6\times {{10}^{-4}}=m\times 2\times {{10}^{-5}} $
$ \
Therefore m=30 A-m $ Now, $ \ell =\frac{M}{m}=\frac{3}{30}=0.1m $
BETA
