Magnetism Question 192
Question: A short bar magnet placed with its axis at 30° with a uniform external magnetic field of 0.16 Tesla experiences a torque of magnitude 0.032 Joule. The magnetic moment of the bar magnet will be
[MP PMT 1997; UPSEAT 2004]
Options:
A) 0.23 Joule/Tesla
B) 0.40 Joule/Tesla
C) 0.80Joule/Tesla
D) Zero
Show Answer
Answer:
Correct Answer: B
Solution:
$ \tau =MB _{H}\sin \theta \Rightarrow 0.032=M\times 0.16\times \sin 30^{o} $
$ \Rightarrow M=0.4J/tesla $
BETA
