Magnetism Question 113
Question: The time period of a freely suspended magnet is 2 sec. If it is broken in length into two equal parts and one part is suspended in the same way, then its time period will be
[MP PMT 1999]
Options:
A) 4 seconds
B) 2 seconds
C) $ \sqrt{2}\sec{\theta} $
D) 1 sec
Show Answer
Answer:
Correct Answer: D
Solution:
$ {T}’=\frac{T}{n}\Rightarrow {T}’=\frac{2}{2}=1sec $
BETA
