Magnetism Question 256
Question: A dip needle lies initially in the magnetic meridian when it shows an angle of dip $ \theta $ at a place. The dip circle is rotated through an angle x in the horizontal plane and then it shows an angle of dip $ \theta $ . Then $ \frac{\tan ,\theta ‘}{\tan ,\theta } $ is
Options:
A) $ \frac{1}{\cos ,x} $
B) $ \frac{1}{\sin ,x} $
C) $ \frac{1}{\tan ,x} $
D) $ \cos ,x $
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Answer:
Correct Answer: A
Solution:
[a] $ \tan ,\theta =\frac{V}{H} $ , $ \tan ,{{\theta }^{’}}=\frac{V}{H,\cos ,x} $ ; $ \frac{\tan {{\theta }^{’}}}{\tan ,\theta }=\frac{1}{\cos ,x} $
BETA
