Nuclear Physics And Radioactivity Question 133

Question: The masses of neutron and proton are 1.0087 a.m.u. and 1.0073 a.m.u. respectively. If the neutrons and protons combine to form a helium nucleus (alpha particles) of mass 4.0015 a.m.u. The binding energy of the helium nucleus will be (1 a.m.u.= 931MeV) [CPMT 1986; MP PMT 1995; CBSE PMT 2003]

Options:

A) 28.4 MeV

B) 20.8 MeV

C) 27.3 MeV

D) 14.2 MeV

Show Answer

Answer:

Correct Answer: A

Solution:

B.E.= Dmc2 $ =[2(1.0087+1.0073)-4.0015]=28.4\ MeV $



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