Nuclear Physics And Radioactivity Question 214
Question: To generate a power of 3.2 mega watt, the number of fissions of $ U^{235} $ per minute is (Energy released per fission = 200MeV, $ 1eV=1.6\times {{10}^{-19}}J) $ [EAMCET (Engg.) 2000]
Options:
A) $ 6\times 10^{18} $
B) $ 6\times 10^{17} $
C) $ 10^{17} $
D) $ 6\times 10^{16} $
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Answer:
Correct Answer: A
Solution:
Number of fissions per second $ =\frac{Power\ output}{Energy\ released\ per\ fission} $ $ =\frac{3.2\times 10^{6}}{200\times 10^{6}\times 1.6\times {{10}^{-19}}}=1\times 10^{17} $
$ \Rightarrow $ Number of fission per minute $ =60\times 10^{17}=6\times 10^{18} $
BETA
