Nuclear Physics And Radioactivity Question 218
Question: The energy liberated on complete fission of 1 kg of $ _{92}U^{235} $ is (Assume 200 MeV energy is liberated on fission of 1 nucleus) [UPSEAT 2003]
Options:
A) $ 8.2\times 10^{10}J $
B) $ 8.2\times 10^{9}J $
C) $ 8.2\times 10^{13}J $
D) $ 8.2\times 10^{16}J $
Show Answer
Answer:
Correct Answer: C
Solution:
Mass of a uranium nucleus $ =92\times 1.6725\times {{10}^{-27}}+143\times 1.6747\times {{10}^{-27}} $ $ =393.35\times {{10}^{-27}}kg $ Number of nuclei in the given mass $ =\frac{1}{393.35\times {{10}^{-27}}}=2.542\times 10^{24} $ Energy released $ =200\times 2.542\times 10^{24}MeV $ $ =5.08\times 10^{26}MeV=8.135\times 10^{13}J=8.2\times 10^{13}J $
BETA
