Nuclear Physics And Radioactivity Question 233
In a nuclear reactor, the fuel is consumed at the rate of 1 mg/s. The power generated in kilowatt is 1.5 [DCE 2003]
Options:
A) $ 9\times 10^{4} $
B) $ 9\times 10^{7} $
C) $ 9\times 10^{8} $
D) $ 9\times 10^{12} $
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Answer:
Correct Answer: B
Solution:
Power $ P=\frac{Energy}{time}=\frac{mc^{2}}{t}, $ = 1 ´ 10?6´ (3 ´ 108)2 = 9 ´ 1016 W = 9 ´ 1013 kW.
BETA
