Nuclear Physics And Radioactivity Question 28
Question: An energy of 24.6 eV is required to remove one of the electrons from a neutral helium atom. The energy (in eV) required to remove both the electrons from a neutral helium atom is [IIT 1995]
Options:
A) 79.0
B) 51.8
C) 49.2
D) 38.2
Show Answer
Answer:
Correct Answer: A
Solution:
After the removal of first electron remaining atom will be hydrogen like atom. So energy required to remove second electron from the atom $ E=13.6\times \frac{2^{2}}{1}=54.4,eV $ \ Total energy required = 24.6 + 54.4 = 79 eV.
BETA
