Nuclear Physics And Radioactivity Question 29
Question: A hydrogen atom in its ground state absorbs 10.2 eV of energy. The orbital angular momentum is increased by [MP PET 1995; MP PMT 1997]
Options:
A) $ 1.05\times {{10}^{-34}} $ J-sec
B) $ 3.16\times {{10}^{-34}} $ J-sec
C) $ 2.11\times {{10}^{-34}} $ J-sec
D) $ 4.22\times {{10}^{-34}} $ J-sec (Given Planck constant $ h=6.6\times {{10}^{-34}}J- $ sec)
Show Answer
Answer:
Correct Answer: A
Solution:
Electron after absorbing 10.2 eV energy goes to its first excited state (n=2) from ground state (n = 1).
$ \therefore $ Increase in momentum $ =\frac{h}{2\pi } $ $ =\frac{6.6\times {{10}^{-34}}}{6.28}=1.05\times {{10}^{-34}}J\text{-}s $ .
BETA
