Nuclear Physics And Radioactivity Question 323
Question: The nucleus $ _{48}^{115}Cd $ after two successive $ {\beta }^{-} $ decays will give [CBSE PMT 1992; JIPMER 2000]
Options:
A) $ _{46}^{115}Pa $
B) $ _{49}^{114}In $
C) $ _{50}^{113}Sn $
D) $ _{50}^{115}Sn $
Show Answer
Answer:
Correct Answer: D
Solution:
$ {48}Cd^{115}{{\xrightarrow{{2 -1}{{\beta }^{o}}}}_{,50}}Sn^{115} $
BETA
