Nuclear Physics And Radioactivity Question 35
Question: What is the radius of iodine atom (at. no. 53, mass number 126) [CBSE PMT 1993]
Options:
A) $ 2.5\times {{10}^{-11}}m $
B) $ 2.5\times {{10}^{-9}}m $
C) $ 7\times {{10}^{-9}}m $
D) $ 7\times {{10}^{-6}}m $
Show Answer
Answer:
Correct Answer: A
Solution:
Electronic configuration of iodine is 2, 8, 18, 18, 7, Here $ r_{n}=(0.053\times {{10}^{-9}}m)\frac{n^{2}}{Z} $ Here $ n=5 $ and $ {Z-1}{{X}^{A-4}}{{\xrightarrow{{0}{{\gamma }^{0}}}}{Z-1}}{{X}^{A-4}} $ hence $ r{n}=2.5\times {{10}^{-11}}m $ .
BETA
