Nuclear Physics And Radioactivity Question 350
Question: In the given nuclear reaction, how many a and b particles are emitted $ _{92}X^{235}\to {\ _{82}}Y^{207} $ [AFMC 2001]
Options:
A) 3a particles and 2b particle
B) 4a particles and 3b particle
C) 6a particles and 4b particle
D) 7a particles and 4b particle
Show Answer
Answer:
Correct Answer: D
Solution:
$ {n_{\alpha }}=\frac{A-A’}{4}=\frac{235-207}{4}=7 $ $ {n_{\beta }}=(2{n_{\alpha }}-Z+Z’)=(2\times 7-92+82)=4 $
BETA
