Nuclear Physics And Radioactivity Question 357
Question: 99% of a radioactive element will decay between [AMU (Engg.) 2001]
Options:
A) 6 and 7 half lives
B) 7 and 8 half lives
C) 8 and 9 half lives
D) 9 half lives
Show Answer
Answer:
Correct Answer: A
Solution:
$ N=N_{0}{{( \frac{1}{2} )}^{n}}\Rightarrow \frac{N}{N_{0}}={{( \frac{1}{2} )}^{n}} $
$ \Rightarrow \frac{1}{100}={{( \frac{1}{2} )}^{n}}\Rightarrow 2^{n}=100 $ n comes out in between 6 and 7.
BETA
