Nuclear Physics And Radioactivity Question 36
Question: If in Rutherford?s experiment, the number of particles scattered at $ 90^{o} $ angle are 28 per min, then number of scattered particles at an angle $ 60^{o} $ and $ 120^{o} $ will be [UPSEAT 1999]
Options:
A) 112/min, 12.5/min
B) 100/min, 200/min
C) 50/min, 12.5/min
D) 117/min, 25/min
Show Answer
Answer:
Correct Answer: A
Solution:
$ N\propto [ \frac{1}{{{\sin }^{4}}\theta /2} ] $
Þ $ N_{1}=7\times \frac{1}{{{(\sin 30^{o})}^{4}}}=112 $ and $ N_{2}=7\times \frac{1}{{{(\sin 60^{o})}^{4}}}=12.5 $ .
BETA
