Nuclear Physics And Radioactivity Question 360

Question: In the disintegration series $ {92}^{238}U\xrightarrow{\alpha }x\xrightarrow{\beta }{Z}^{A}y $ The value of Z and A respectively will be [MP PET 2001; MP PMT 2001]

Options:

A) 92, 236

B) 88, 230

C) 90, 234

D) 91, 234

Show Answer

Answer:

Correct Answer: D

Solution:

$ _{92}U^{238}\to _{2}He^{4}+ _{90}X^{234}\to _{-1}e^{0}+ _{91}U^{234} $ Hence, A = 234, Z = 91