Nuclear Physics And Radioactivity Question 360
Question: In the disintegration series $ {92}^{238}U\xrightarrow{\alpha }x\xrightarrow{\beta }{Z}^{A}y $ The value of Z and A respectively will be [MP PET 2001; MP PMT 2001]
Options:
A) 92, 236
B) 88, 230
C) 90, 234
D) 91, 234
Show Answer
Answer:
Correct Answer: D
Solution:
$ _{92}U^{238}\to _{2}He^{4}+ _{90}X^{234}\to _{-1}e^{0}+ _{91}U^{234} $ Hence, A = 234, Z = 91