Nuclear Physics And Radioactivity Question 368
Question: The ratio activity of an element becomes 1/64th of its original value in 60 sec. Then the half life period is [MP PMT 2002]
Options:
A) 5 sec
B) 10 sec
C) 20 sec
D) 30 sec
Show Answer
Answer:
Correct Answer: B
Solution:
$ A=A_{0}{{( \frac{1}{2} )}^{\frac{t}{{T_{1/2}}}}}\Rightarrow \frac{1}{64}={{( \frac{1}{2} )}^{\frac{60}{{T_{1/2}}}}} $
$ \Rightarrow {{( \frac{1}{2} )}^{6}}={{( \frac{1}{2} )}^{\frac{60}{{T_{1/2}}}}}\Rightarrow {T_{1/2}}=10\sec $