Nuclear Physics And Radioactivity Question 368

Question: The ratio activity of an element becomes 1/64th of its original value in 60 sec. Then the half life period is [MP PMT 2002]

Options:

A) 5 sec

B) 10 sec

C) 20 sec

D) 30 sec

Show Answer

Answer:

Correct Answer: B

Solution:

$ A=A_{0}{{( \frac{1}{2} )}^{\frac{t}{{T_{1/2}}}}}\Rightarrow \frac{1}{64}={{( \frac{1}{2} )}^{\frac{60}{{T_{1/2}}}}} $
$ \Rightarrow {{( \frac{1}{2} )}^{6}}={{( \frac{1}{2} )}^{\frac{60}{{T_{1/2}}}}}\Rightarrow {T_{1/2}}=10\sec $