Nuclear Physics And Radioactivity Question 369
Question: If $ _{92}U^{238} $ undergoes successively 8 a-decays and 6 b-decays, then resulting nucleus is [CBSE PMT 2002]
Options:
A) $ _{82}U^{206} $
B) $ _{82}Pb^{206} $
C) $ _{82}U^{210} $
D) $ _{82}U^{214} $
Show Answer
Answer:
Correct Answer: B
Solution:
$ {(Z=92)}{{U}^{(A=238)}}{{\xrightarrow{(8\alpha ,,6\beta )}}{{{Z}’}}}{{X}^{{{A}’}}} $ so $ {A}’=A-4{n_{\alpha }} $ = 238 ? 4 ´ 8 = 206 and $ {Z}’={n_{\beta }}-2{n_{\alpha }}+z $ = 6 ? 2 ´ 8 + 92 = 82.
BETA
