Nuclear Physics And Radioactivity Question 378
Question: A nucleus with Z = 92 emits the following in a sequence: $ \alpha ,,{{\beta }^{-}},,{{\beta }^{-}},,\alpha ,\alpha ,\alpha ,\alpha ,\alpha ,{{\beta }^{-}},,{{\beta }^{-}},\alpha ,,{{\beta }^{+}},,{{\beta }^{+}},,\alpha $ . The Z of the resulting nucleus is [AIEEE 2003]
Options:
A) 74
B) 76
C) 78
D) 82
Show Answer
Answer:
Correct Answer: C
Solution:
$ {Z_{Resuting\ nucleus}}=92-8\times 2+4\times 1-2\times 1=78 $
BETA
