Nuclear Physics And Radioactivity Question 387
Question: A radioactive material has a half-life of 10 days. What fraction of the material would remain after 30 days [AIIMS 2005]
Options:
A) 0.5
B) 0.25
C) 0.125
D) 0.33
Show Answer
Answer:
Correct Answer: C
Solution:
$ N=N_{0}{{( \frac{1}{2} )}^{\frac{t}{{T_{1/2}}}}} $
$ \Rightarrow \frac{N}{N_{0}}={{( \frac{1}{2} )}^{\frac{30}{10}}}=\frac{1}{8}=0.125 $ .
BETA
