Nuclear Physics And Radioactivity Question 392
Question: A nucleus of mass 218 amu in free state decays to emit an a-particle. Kinetic energy of the a-particle emitted is 6.7 MeV. The recoil energy (in MeV) of the daughter nucleus is [EAMCET 2005]
Options:
A) 1.0
B) 0.5
C) 0.25
D) 0.125
Show Answer
Answer:
Correct Answer: D
Solution:
Using conservation of momentum $ P_{daughter}={P_{\alpha }} $
Þ $ \frac{E_{d}}{{E_{\alpha }}}=\frac{{m_{\alpha }}}{m_{d}} $
Þ $ E_{d}=\frac{{E_{\alpha }}\times {m_{\alpha }}}{m_{d}} $ $ =\frac{6.7\times 4}{214}=0.125,MeV $
BETA
