Nuclear Physics And Radioactivity Question 393
Question: $ C^{14} $ has half-life 5700 years. At the end of 11400 years, the actual amount left is [MP PET 2005]
Options:
A) 0.5 of original amount
B) 0.25 of original amount
C) 0.125 of original amount
D) 0.0625 of original amount
Show Answer
Answer:
Correct Answer: B
Solution:
$ N=N_{0}\times {{( \frac{1}{2} )}^{11400/5700}} $ $ =N_{0}{{( \frac{1}{2} )}^{2}} $ $ =0.25N_{0} $ .