Nuclear Physics And Radioactivity Question 393

Question: $ C^{14} $ has half-life 5700 years. At the end of 11400 years, the actual amount left is [MP PET 2005]

Options:

A) 0.5 of original amount

B) 0.25 of original amount

C) 0.125 of original amount

D) 0.0625 of original amount

Show Answer

Answer:

Correct Answer: B

Solution:

$ N=N_{0}\times {{( \frac{1}{2} )}^{11400/5700}} $ $ =N_{0}{{( \frac{1}{2} )}^{2}} $ $ =0.25N_{0} $ .