Nuclear Physics And Radioactivity Question 411
Question: The mass of $ _{7}N^{15} $ is 15.00011 amu, mass of $ _{8}O^{16} $ is 15.99492 amu and $ mp=1.00783amu $ Determine binding energy of last proton of $ _{8}O^{16} $ .
Options:
A) 2.13 MeV
B) 0.13 MeV
C) 10 MeV
D) 12.13 MeV
Show Answer
Answer:
Correct Answer: D
Solution:
[d] $ M{({8}}O^{16})=M{({7}}N^{15})+1m_{P} $ binding energy of last proton $ =M(N^{15})+m_{P}-M{(_{1}}O^{16}) $ $ =15.00011+1.00783-15.99492 $ $ =0.01302amu=12.13MeV $
BETA
