Nuclear Physics And Radioactivity Question 456
Two radioactive substances X and Y emit $ \alpha $ and $ \beta $ particles respectively. Their disintegration constants are in the ratio 2 : 3. To have equal probabilities of getting emission of $ \alpha $ and $ \beta $ particles, the ratio of number of atoms X to that of Y at any time instant is
Options:
A) 2 : 3
B) 3 : 2
C) e : 2.71828…
D) (e-1) : 1
Show Answer
Answer:
Correct Answer: B
Solution:
[b] $ N_{1}{\lambda_{1}}=N_{2}{\lambda_{2}}\frac{{\lambda_{1}}}{{\lambda_{2}}}=\frac{2}{3}\Rightarrow \frac{N_{2}}{N_{1}}=\frac{2}{3} $
$ \Rightarrow $ ratio of no. of nuclei of X to that of $ Y=3/2 $
BETA
