Nuclear Physics And Radioactivity Question 485
Question: If the binding energy per nucleon in $ Li^{7} $ and $ He^{4} $ nuclei are respectively 5.60 MeV and 7.06 MeV, then energy of reaction $ Li^{7}+p\to 2{\ _{2}}He^{4} $ is
Options:
A) 19.6 MeV
B) 2.4 MeV
C) 8.4 MeV
D) 17.3 MeV
Show Answer
Answer:
Correct Answer: D
Solution:
[d] B.E. of $ Li^{7}=39.20\ MeV $ and $ He^{4}=28.24\ MeV $ Hence binding energy of $ 2He^{4}=56.48\ MeV $ Energy of reaction $ =56.48-39.20=17.28\ MeV $ .
BETA
