Nuclear Physics And Radioactivity Question 490
Question: In the reaction $ _{1}^{2}H+ _{1}^{3}H\to _{2}^{4}He+ {0}^{1}n $ . If the tending energies of $ {1}^{2}H,{1}^{3}H\text{ and }{2}^{4}He $ are respectively $ a,\text{ b and }c $ (in MeV), then the energy (in MeV) released in this reaction is
Options:
A) $ c+a-b $
B) $ c-a-b $
C) $ a+b+c $
D) $ a+b-c $
Show Answer
Answer:
Correct Answer: B
Solution:
[b] During fusion binding energy of daughter nucleus is always greater than the total energy of the parent nuclei so energy released = c (a + b) = c a b
BETA
