Nuclear Physics And Radioactivity Question 495
Question: In the given nuclear reaction A, B, C, D, E represents $ {92}U^{238}{{\xrightarrow{\alpha }}{B}}Th^{A}{{\xrightarrow{\beta }}{D}}Pa^{C}{{\xrightarrow{E}}{92}}U^{234} $
Options:
A) A = 234, B = 90, C = 234, D = 91, E = $ \beta $
B) A = 234, B = 90, C = 238, D = 94, E = $ \alpha $
C) A = 238, B = 93, C = 234, D = 91, E = $ \beta $
D) A = 234, B = 90, C = 234, D = 93, E = $ \alpha $
Show Answer
Answer:
Correct Answer: A
Solution:
[a] $ _{92}U^{238}\xrightarrow{\alpha } _{90}Th^{234},\xrightarrow{\beta } {91}Pa^{234} $ $ \xrightarrow{E{({-1}}{{\beta }^{o}})} _{92}U^{234} $
BETA
