Nuclear Physics And Radioactivity Question 84
Question: A radioactive nucleus is being produced at a constant rate a per second. Its decay constant is l. If N0 are the number of nuclei at time t = 0, then maximum number of nuclei possible are
Options:
A) $ \frac{\alpha }{\lambda } $
B) $ N_{0}+\frac{\alpha }{\lambda } $
C) N0
D) $ \frac{\lambda }{\alpha }+N_{0} $
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Answer:
Correct Answer: A
Solution:
Maximum number of nuclei will be present when rate of decay = rate of formation
Þ $ \lambda N=\alpha $
Þ $ N=\frac{\alpha }{\lambda } $
BETA
