Optics Question 1028
Question: If the ratio of amplitude of two waves is 4 : 3, then the ratio of maximum and minimum intensity is
[AFMC 1997]
Options:
A) 16 : 18
B) 18 : 16
C) 49 : 1
D) 94 : 1
Show Answer
Answer:
Correct Answer: C
Solution:
$ \frac{{I _{\max }}}{{I _{\min }}}={{( \frac{\frac{a _{1}}{a _{2}}+1}{\frac{a _{1}}{a _{2}}-1} )}^{2}}={{( \frac{\frac{4}{3}+1}{\frac{4}{3}-1} )}^{2}}=\frac{49}{1} $
BETA
