Optics Question 1105
Question: In Young’s double slit experiment, the distance between the two slits is 0.1 mm and the wavelength of light used is $ 4\times {{10}^{-7}}m $ . If the width of the fringe on the screen is 4 mm, the distance between screen and slit is
[Bihar CMEET 1995]
Options:
A) 0.1 mm
B) 1 cm
C) 0.1 cm
D) 1 m
Show Answer
Answer:
Correct Answer: D
Solution:
$ \beta =\frac{\lambda D}{d}\Rightarrow (4\times {{10}^{-3}})=\frac{4\times {{10}^{-7}}\times D}{0.1\times {{10}^{-3}}}\Rightarrow D=1m $
BETA
