Optics Question 1106
Question: In Young’s double slit experiment, the distance between sources is 1 mm and distance between the screen and source is 1 m. If the fringe width on the screen is 0.06 cm, then l =
[CPMT 1996]
Options:
A) $ 6000{AA} $
B) $ 4000{AA} $
C) $ 1200{AA} $
D) $ 2400{AA} $
Show Answer
Answer:
Correct Answer: A
Solution:
$ \beta =\frac{\lambda D}{d}\Rightarrow (0.06\times {{10}^{-2}})=\frac{\lambda \times 1}{1\times {{10}^{-3}}} $
$ \Rightarrow \lambda =6000{AA} $
BETA
