Optics Question 1145
Question: In Young’s double slit experiment, distance between two sources is 0.1 mm. The distance of screen from the sources is 20 cm. Wavelength of light used is 5460 Å. Then angular position of the first dark fringe is
[DCE 2002]
Options:
A) 0.08°
B) 0.16°
C) 0.20°
D) 0.313°
Show Answer
Answer:
Correct Answer: D
Solution:
Angular position of first dark fringe $ \theta =\frac{\lambda }{d}=\frac{5460\times {{10}^{-10}}}{0.1\times {{10}^{-3}}}\times \frac{180}{\pi } $ (in degree) = 0.313°
BETA
