Optics Question 1146
Question: In a Young’s double slit experiment, the slit separation is 0.2 cm, the distance between the screen and slit is 1m. Wavelength of the light used is 5000 Å. The distance between two consecutive dark fringes (in mm) is
[DCE 2004]
Options:
A) 0.25
B) 0.26
C) 0.27
D) 0.28
Show Answer
Answer:
Correct Answer: A
Solution:
Distance between two consecutive dark fringes $ \beta =\frac{\lambda D}{d} $
$ =\frac{5000\times {{10}^{-10}}\times 1}{0.2\times {{10}^{-2}}}=0.25 $ mm.
BETA
