Optics Question 1150

Question: In Young double slit experiment, when two light waves form third minimum, they have

[RPMT 2003]

Options:

A) Phase difference of $ 3\pi $

B) Phase difference of $ \frac{5\pi }{2} $

C) Path difference of $ 3\lambda $

D) Path difference of $ \frac{5\lambda }{2} $

Show Answer

Answer:

Correct Answer: D

Solution:

For minima, path difference $ \Delta =(2n-1)\frac{\lambda }{2} $

For third minima $ n=3\Rightarrow \Delta =(2\times 3-1)\frac{\lambda }{2}=\frac{5\lambda }{2} $



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