A) 2.0 cm above P
B) 1.5 cm above P
C) 2.0 cm below P
D) 1 cm above P
Correct Answer: D
The two slabs will shift the image a distance $ d=2( 1-\frac{1}{\mu } )t=2( 1-\frac{1}{1.5} )( 1.5 )=1cm $
Therefore, final image will be 1 cm above point P.
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