Optics Question 236
Question: A star producing light of wavelength $ 6000{\mathring{A}} $ moves away from the earth with a speed of 5 km/sec. Due to Doppler effect the shift in wavelength will be $ (c=3\times 10^{8}m/\sec ) $
[MP PMT 1990]
Options:
A) $ 0.1{\mathring{A}} $
B) $ 0.05{\mathring{A}} $
C) $ 0.2{\mathring{A}} $
D) $ 1{\mathring{A}} $
Show Answer
Answer:
Correct Answer: A
Solution:
Doppler’s shift is given by $ \Delta \lambda =\frac{v\lambda }{c}=\frac{5000\times 6000}{3\times 10^{8}}=0.1{\mathring{A}} $
BETA
