Optics Question 259
A rocket is going away from the earth at a speed of 106 m/s. If the wavelength of the light wave emitted by it be $ 5700\AA $ , what will be its Doppler shift
[RPMT 1996]
Options:
A) $ 200{AA} $
B) $ 19{AA} $
C) $ 20{AA} $
D) $ 0.2\text{AA} $
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Answer:
Correct Answer: B
Solution:
$ \frac{\Delta \lambda }{\lambda }=\frac{v}{c} $
Therefore $ \Delta \lambda =\frac{5700\times 10^{6}}{3\times 10^{8}}=19{AA} $
BETA
