Optics Question 316
Question: A TV tower has a height of 100 m. The average population density around the tower is 1000 per km2. The radius of the earth is $ 6.4\times 10^{6} $ m. the population covered by the tower is
Options:
A) $ 2\times 10^{6} $
B) $ 3\times 10^{6} $
C) $ 4\times 10^{6} $
D) $ 6\times 10^{6} $
Show Answer
Answer:
Correct Answer: C
Solution:
Population covered = 2phR ´ Population density = 2p ´ 100 ´ 6.4 ´ 106 ´ $ \frac{1000}{{{(10^{3})}^{2}}} $ = 4 ´ 106
BETA
