Optics Question 377
Question: The diameter of the objective of the telescope is 0.1 metre and wavelength of light is 6000 Å. Its resolving power would be approximately
[MP PET 1997]
Options:
A) $ 7.32\times {{10}^{-6}}rad $
B) $ 1.36\times 10^{6}rad $
C) $ 7.32\times {{10}^{-5}}rad $
D) $ 1.36\times 10^{5}rad $
Show Answer
Answer:
Correct Answer: D
Solution:
Resolving power $ =\frac{d}{1.22\ \lambda }=\frac{0.1}{1.22\times 6000\times {{10}^{-10}}} $
$ \cong 1.36\times 10^{5}radian $
BETA
