Optics Question 486

The maximum illumination on a screen at a distance of 2 m from a lamp is 25 lux. The value of total luminous flux emitted by the lamp is 1000 lumens

[JIMPER 1997]

Options:

A) 1256 lumen

B) 1600 lumen

C) 100 candela

D) 400 lumen

Show Answer

Answer:

Correct Answer: A

Solution:

$ I=\frac{L}{r^{2}} $

$ \Rightarrow L=I\cdot r^{2} $

$ =22\times 2^{2}=88 $ .

Now $ \varphi =4\pi L=4\times 3.14\times 100 $ = 1256.64 lumen.



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