Optics Question 546
Question: The angle of polarization for any medium is 60o, what will be critical angle for this
[UPSEAT 1999]
Options:
A) $ {{\sin }^{-1}}\sqrt{3} $
B) $ {{\tan }^{-1}}\sqrt{3} $
C) $ {{\cos }^{-1}}\sqrt{3} $
D) $ {{\sin }^{-1}}\frac{1}{\sqrt{3}} $
Show Answer
Answer:
Correct Answer: D
Solution:
By using $ \mu =\tan {\theta _{p}}\Rightarrow \mu =\tan 60=\sqrt{3} $ , also $ C={{\sin }^{-1}}( \frac{1}{\mu } )\Rightarrow C={{\sin }^{-1}}( \frac{1}{\sqrt{3}} ) $
BETA
