Optics Question 604
The radius of curvature of convex surface of a thin plano-convex lens is 15 cm and refractive index of its material is 1.6. The power of the lens will be 10 D
[MP PMT 1994]
Options:
A) $ +1D $
B) $ -2D $
C) $ +3D $
D) $ +4D $
Show Answer
Answer:
Correct Answer: D
Solution:
$ f=\frac{R}{(\mu -1)}=\frac{15}{(1.6-1)}=25cm $
$ \therefore P=\frac{100}{f}=\frac{100}{25}=+4D $
BETA
