Optics Question 633

Question: The image distance of an object placed 10 cm in front of a thin lens of focal length + 5 cm is

[SCRA 1994]

Options:

A) 6.5 cm

B) 8.0 cm

C) 9.5 cm

D) 10.0 cm

Show Answer

Answer:

Correct Answer: D

Solution:

$ \frac{1}{f}=\frac{1}{v}-\frac{1}{u} $

$ \Rightarrow $ $ \frac{1}{+5}=\frac{1}{v}-\frac{1}{(-10)}\Rightarrow v=10 $ $ cm $



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