Optics Question 667
A point object O is placed in front of a glass rod having a spherical end of radius of curvature 30 cm. The image would be formed at
[Odisha JEE 2002]
Options:
A) 30 cm left
B) Infinity
C) 1 cm to the right
D) 18 cm to the left
Show Answer
Answer:
Correct Answer: A
Solution:
By using formula $ \frac{{\mu _{2}}}{v}-\frac{{\mu _{1}}}{u}=\frac{{\mu _{2}}-{\mu _{1}}}{R} $
$ \Rightarrow $ $ \frac{1.5}{v}-\frac{1}{(-15)}=\frac{(1.5-1)}{+30}\Rightarrow v=-30cm $ .
Negative sign shows that the image is obtained on the same side of the object, i.e., towards the left.
BETA
