Optics Question 943
In the given graph of the above question, find the value of angle $ i _{1} $ in degrees.
Options:
A) $ 40^{o} $
B) $ 60^{o} $
C) $ 70^{o} $
D) $ 90^{o} $
Show Answer
Answer:
Correct Answer: D
Solution:
When angle of incidence is $ i _{1}=40^{o} $ (from reversibility of ray) also $ \delta =70^{o} $
$ \Rightarrow $ $ 70^{o}=i _{1}+40^{o}-A\Rightarrow i _{1}=30^{o} $
BETA
