Optics Question 969
Question: A diver at a depth of 12m in water ( $ \mu =4/3) $ sees the sky in a cone of semi-vertical angle
[KCET 1999; Pb. PMT 2002; MP PMT 1995, 2003]
Options:
A) $ {{\sin }^{-1}}(4/3) $
B) $ {{\tan }^{-1}}(4/3) $
C) $ {{\sin }^{-1}}(3/4) $
D) 90°
Show Answer
Answer:
Correct Answer: C
Solution:
Semi vertical angle $ =C={{\sin }^{-1}}( \frac{1}{\mu } )={{\sin }^{-1}}( \frac{3}{4} ) $
BETA
