Wave Mechanics Vibration Of String Question 8
Question: A string is producing transverse vibration whose equation is $ y=0.021\ \sin (x+30t) $ , Where x and y are in meters and $ t $ is in seconds. If the linear density of the string is $ 1.3\times {{10}^{-4}} $ kg/m, then the tension in the string in $ N $ will be
[RPET 1999; RPMT 2002]
Options:
A) 10
B) 0.5
C) 1
D) 0.117
Show Answer
Answer:
Correct Answer: D
Solution:
$ y=0.021\sin (x+30t) $
Therefore $ v=\frac{\omega }{k}=\frac{30}{1}=30m/s $ .
Using, $ v=\sqrt{\frac{T}{m}}\Rightarrow 30=\sqrt{\frac{T}{1.3\times {{10}^{-4}}}}\Rightarrow T=0.117 $ N
BETA
