wave_mechanics basics_of_mechanical_waves Question 94
Question: Ultrasonic signal sent from SONAR returns to it after reflection from a rock after a lapse of 1 sec. If the velocity of ultrasound in water is 1600 ms?1, the depth of the rock in water is
[JIPMER 2000]
Options:
A) 300 m
B) 400 m
C) 500 m
D) 800 m
Show Answer
Answer:
Correct Answer: D
Solution:
If d is the distance of rock from SONAR then $ 2d=vt $
Therefore $ d=\frac{v\times t}{2}=\frac{1600\times 1}{2}=800m $
BETA
